GoAhead是一个轻量级的Web服务器,它的源代码可以在GitHub上找到,以下是一个简单的GoAhead源码解析:
1、我们需要包含必要的头文件:
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <unistd.h> #include <sys/socket.h> #include <netinet/in.h> #include <arpa/inet.h> #include <time.h>
2、定义一些常量和全局变量:
#define PORT 8080 #define BUFFER_SIZE 1024 #define HTTP_OK "HTTP/1.1 200 OK ContentType: text/html " #define HTTP_NOT_FOUND "HTTP/1.1 404 Not Found ContentType: text/html " char *http_ok = HTTP_OK; char *http_not_found = HTTP_NOT_FOUND;
3、编写一个简单的HTML响应函数:
void send_response(int client_sock, char *response) { write(client_sock, response, strlen(response)); }
4、编写一个简单的处理请求的函数:
void handle_request(int client_sock) { char buffer[BUFFER_SIZE]; ssize_t bytes_received = read(client_sock, buffer, BUFFER_SIZE 1); if (bytes_received > 0) { buffer[bytes_received] = ' '; printf("Received request: %s ", buffer); if (strncmp(buffer, "GET / HTTP/1.1", 13) == 0) { send_response(client_sock, http_ok); } else { send_response(client_sock, http_not_found); } } }
5、编写主函数,用于启动服务器并监听客户端连接:
int main() { int server_sock, client_sock; struct sockaddr_in server_addr, client_addr; socklen_t client_addr_len = sizeof(client_addr); server_sock = socket(AF_INET, SOCK_STREAM, 0); if (server_sock == 1) { perror("socket"); exit(EXIT_FAILURE); } server_addr.sin_family = AF_INET; server_addr.sin_port = htons(PORT); server_addr.sin_addr.s_addr = INADDR_ANY; if (bind(server_sock, (struct sockaddr *)&server_addr, sizeof(server_addr)) == 1) { perror("bind"); exit(EXIT_FAILURE); } if (listen(server_sock, 10) == 1) { perror("listen"); exit(EXIT_FAILURE); } printf("Server is listening on port %d... ", PORT); while (1) { client_sock = accept(server_sock, (struct sockaddr *)&client_addr, &client_addr_len); if (client_sock == 1) { perror("accept"); continue; } handle_request(client_sock); close(client_sock); } close(server_sock); return 0; }
这个简单的GoAhead服务器只支持一个固定的URL(/
),并且只能处理GET请求,当收到正确的GET请求时,它会返回一个HTTP 200 OK响应,否则返回一个HTTP 404 Not Found响应,这个示例仅用于演示目的,实际的GoAhead服务器实现会更加复杂和健壮。
以上内容就是解答有关“goahead 源码”的详细内容了,我相信这篇文章可以为您解决一些疑惑,有任何问题欢迎留言反馈,谢谢阅读。
原创文章,作者:未希,如若转载,请注明出处:https://www.kdun.com/ask/1188189.html